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程序如下,是用来解线性方程的,用的是高斯赛德乐迭代法做的# u f! ^7 y! R
在算三个未知量的时是和答案一致的,四个未知量就有出入,做六个未知量就出错了.
: @$ T8 K: {2 t2 g谁能告诉我错在哪里了,是题错还是程序错了.8 p7 d7 }# V. t
刚开始学,不足之处请指教。6 _+ d/ }0 y1 Z
#include
1 N5 ^9 r. q, b1 z1 [#include/ N% W" W8 V! p
#define NN 50 ; |$ B; I2 w4 k9 E' Y# B$ \
void main()
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cout.setf(ios::fixed,ios::floatfield);
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int i,j,k;
! @; o" I: R- K5 t double e,c,T,r;8 f a& m! I8 C; r; \" a4 s
//double x[NN],A[NN][NN],B[NN]; Q4 m$ Z" K7 h9 \
//题目如下:任选一个
# g! `3 r& ~: S$ S' ?" B //double x[NN]={0,0,0,0},A[NN][NN]={{0,0,0,0},{0,10,-2,-1},{0,-2,10,-1},{0,-1,-2,5}},B[NN]={0,3,15,10};" e/ W Z% k1 o+ ]8 W* [
double x[NN]={0,0,0,0},A[NN][NN]={{0,0,0,0},{0,10,-1,-2},{0,-1,10,-2},{0,-1,-1,5}},B[NN]={0,7.2,8.3,4.2};
. o% o& [; M0 i //double x[NN]={0,0,0,0,0},A[NN][NN]={{0,0,0,0,0},{0,-5,1,1,2},{0,2,8,1,3},{0,1,-2,-4,-1},{0,-1,3,2,7}},B[NN]={0,-2,-6,6,12};8 `' \5 g1 ?7 S) k0 S
//double x[NN]={0,0,0,0,0,0,0},A[NN][NN]={{0,0,0,0,0,0,0},{0,1,-1,0,-1,0,0},{0,2,4,-1,0,-1,0},{0,4,-1,4,-1,0,-1},{0,8,0,-1,4,-1,0},{0,12,-1,0,-1,4,-1},{0,16,0,-1,0,-1,4}},B[NN]={0,0,5,-2,5,-2,6}; ~- F) a, F7 y& r8 R
//double x[NN]={0,0,0,0,0},A[NN][NN]={{0,0,0,0,0},{0,1,0.333,1.5,-0.333},{0,-2.01,1.45,0.50,2.95},{0,4.32,-1.95,0.007,2.08},{0,5.11,-4.00,3.33,-1.11}},B[NN]={0,3.00,2.62,0.130,3.77};
) M. o3 a4 {& ` //double x[NN]={0,0,0,0},A[NN][NN]={{0,0,0,0},{0,10,3,1},{0,2,-10,3},{0,1,3,10}},B[NN]={0,14,-5,14};
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cout<<"请输入N值:";3 u% ~! }; T( F/ U* D2 ?
cin>>N;- {% C" }' p; g6 I" O! T3 R" S
cout<9 L1 p K! C8 W cin>>e;# z# _+ X& t# N- N0 o7 L
/*cout<$ C5 j2 {1 }; s for(i=1;i<=N;i++)8 B9 j7 K2 G" z* L0 O. y4 m$ k
for(j=1;j<=N;j++)3 v& K/ c! p4 J7 @
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cin>>A[j];
# r2 H7 P) N2 I' }. @! O }
; e8 |# b3 f* m9 @ cout<" a) l K1 a4 X1 e0 ~- a
for(i=1;i<=N;i++)/ t L) N! v: i$ A3 P! N+ p
{' C* ?$ \0 ^* {
for(j=1;j<=N;j++) \, a3 O) U! q+ s0 Q A7 T6 |
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cout<[j]<<' ';3 y1 [$ ~: W k: b: Z
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% G0 h! N! D. J: j4 c( w8 T cout</ p( C8 w9 z$ S# w+ g
}
( o3 k- p# g" P8 {, S/ ~6 U cout<3 b0 L) x) f5 \5 \& \- X1 U; s# w for(i=1;i<=N;i++)cin>>B;
1 P% z- u8 A7 o4 [* B* J1 ^" [1 G for(i=1;i<=N;i++)cout<<<' ';
9 G$ l" h+ q% p9 k! M cout<# S8 Z: d+ r1 |
for(i=1;i<=N;i++)cin>>x;*/! ^/ f. C" }- |6 @! ]
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//cout<<"k"<) G- @( R- l; I; O9 {- U0 @ //for(i=1;i<=N;i++)cout<<"x["<& S/ Y! b: p1 R r=e;
7 P: Z2 ^8 i: D7 w$ g6 H: g for(k=1;r>=e;k++)3 b U/ x ?# w( y
{
- u, o3 _$ B4 y) d0 C+ G r=0;
+ g2 g: r, ]3 F" I4 _ i=1;
2 q5 T* X0 V. S8 x% K9 N for(i=1;i<=N;i++)+ c4 n) ^( ^4 ~
{$ R3 s( I$ B# r% ^: r
T=x; }2 ?0 \9 P4 V) W5 J& u- x) u# T( G
c=0;
4 `" J1 C0 H2 x9 A% I for(j=1;j<=N;j++)( h- }$ J, h* ]" o9 u( ~3 W0 l
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if(j!=i)c+=(A[j]*x[j]);
: t& y7 \3 V8 O+ ~$ Z/ T3 [ cout<<"第"<; ^/ \: t! \$ v6 W2 s ]) d8 m8 `# E
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//c1=0;5 H8 J' v" q, J m7 p6 G
//for(j=1;j<=i-1;j++)c1+=(A[j]*x[j]);2 H. N$ j ?: l# V! X' r4 T
x=(B-c)/A;/ W( w' o% T% d8 e% E; z9 |+ M8 d
cout<<"第"<<. S1 ]: K! K) x3 E. |' V# C if((fabs(x-T))>r)r=fabs(x-T);
" o8 C1 [; G7 u cout<<"第"<% K) m. a* a$ |- s }
" C: e( y9 C( a* { cout</ U W' P8 {/ |7 N //cout<<"k="<" C' \1 Q& m- M4 a( M F
$ Z$ E# m) B) o: d% o7 _, N //cout.setf(ios::fixed,ios::floatfield);+ ~ g9 r7 G9 A) k1 q1 d
for(i=1;i<=N;i++)cout<<"k="<<<' ';//<3 X4 B [2 p4 {& j; l
- F: y# X5 R Y6 N* q) T }cout</ t6 T5 Z8 ]& M" C; ]
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